# Line slope calculator 4x+5y=33

**Straight line given by points A[2; 5] and B[7; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+6.6

**Canonical form of the line equation:**4x+5y-33 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -4t+5 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 8.25

**Y intercept:**y

_{0}= q = 6.6

**Distance line from the origin:**d

_{0}= 5.1537

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[4.5; 3]

**Perpendicular Bisector equation:**5x-4y-10.5 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (7; 1) ; |OB| = 7.0711**

**Scalar product OA .OB = 19**

**Angle ∠ AOB = 60°4'7″ = 1.0484 rad**